leetcode[98]Validate Binary Search Tree

Given a binary tree, determine if it is a valid binary search tree (BST).

Assume a BST is defined as follows:

  • The left subtree of a node contains only nodes with keys less than the node's key.
  • The right subtree of a node contains only nodes with keys greater than the node's key.
  • Both the left and right subtrees must also be binary search trees.

confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
/*
类型名称             字节数         取值范围
signed char            1           -128~+127
short int              2           -32768~+32767
int                    4        -2147438648~+2147438647
long int               4        -2147438648~+2141438647
long long int          8     -9223372036854775808~+9223372036854775807
*/
bool check(TreeNode *node, long long leftmin, long long rightmax)
{
    if(node==NULL)return true;
    return (node->val>leftmin&&node->val<rightmax)&&check(node->left,leftmin,node->val)&&check(node->right,node->val,rightmax);
}
    bool isValidBST(TreeNode *root) {
        return check(root,-9223372036854775808,9223372036854775807);
    }
};
原文地址:https://www.cnblogs.com/Vae1990Silence/p/4281370.html