UVA 621 Secret Research

额。。不理解这题为什么会是数学题 0.0 可能是输入中有很长的字符串需要处理，然后获得字符串的位数是一个需要技巧的过程？不过我直接STL过的。。。真心感觉STL很方便但是也不能依赖STL额。。顺便总结一下输出的时候如果没要求最后不输出回车最后一定要输出回车否则就会WAWAWA 我在这栽了三次 = =

以下是题和AC代码

Secret Research

At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

`positive result', `negative result', `experiment failed' or `experiment not completed'

The encrypted result constitutes a string of digits S, which may take one of the following forms:



positive result 		 S = 1 or S = 4 or S = 78 

negative result 		 S = S35 

experiment failed 		 S = 9S4 

experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

You are to write a program which decrypts given sequences of digits.

Input

A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings.

Output

For each analysed sequence of digits the following lines should be sent to output (in separate lines):


		 + 		  for a positive result
		 - 		  for a negative result
		 * 		  for a failed experiment
		 ? 		  for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

Sample Input

Sample Output

+
-
?
*

 1 #include<iostream>
 2 #include<string>
 3 #include<stdlib.h>
 4 #include<stdio.h>
 5 using namespace std;
 6 
 7 int main(void)
 8 {
 9     //freopen("621.in", "r", stdin);
10     long long n;
11     scanf("%lld", &n);
12     for (long long i = 0; i < n; i++)
13     {
14         string s;
15         int flag;
16         cin >> s;
17         if (s == "1" || s == "4" || s == "78") { printf("+
");  continue; }
18         else if (s[s.size() - 1] == '5' && s[s.size() - 2] == '3') { printf("-
"); continue; }
19         else if (s[0] == '9' && s[s.size() - 1] == '4') { printf("*
");  continue; }
20         else if (s[0] == '1' && s[1] == '9' && s[2] == '0') { printf("?
");  continue; }
21         
22     }
23     //system("pause");
24     return 0;
25 }