Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
就是计算a+b然后输出的水题,要注意符号判断,如果为0的话就输出一个0就可以了.
做任何题都要小心结果会不会就是一个0,还有一个0不算是前导0.
#include <iostream>
#include <bits/stdc++.h>
#define de(x) cout<<#x<<" "<<(x)<<endl
using namespace std;
int a[10];
int cur=0;
int main()
{
int n,m;
scanf("%d%d",&n,&m);
int sum=n+m;
bool sign_flag=true;
bool zero_flag=false;
if(sum==0)zero_flag=true;
if(sum<0)sign_flag=false,sum=-sum;///
while(sum>0)
{
a[cur++]=sum%10;
sum/=10;
}
if(!sign_flag)printf("-");
int cnt=0;
for(int i=cur-1;i>=0;i--)
{
printf("%d",a[i]);
cnt++;
if(i%3==0&&i!=0)
{
printf(",");
}
}
if(zero_flag)printf("0");
printf("
");
return 0;
}