Substrings

 Substrings
Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u
Submit Status

Description

You are given a number of case-sensitive strings of alphabetic characters, find the largest string X, such that either X, or its inverse can be found as a substring of any of the given strings. 
 

Input

The first line of the input file contains a single integer t (1 <= t <= 10), the number of test cases, followed by the input data for each test case. The first line of each test case contains a single integer n (1 <= n <= 100), the number of given strings, followed by n lines, each representing one string of minimum length 1 and maximum length 100. There is no extra white space before and after a string. 
 

Output

There should be one line per test case containing the length of the largest string found. 
 

Sample Input

2 3 ABCD BCDFF BRCD 2 rose orchid
 

Sample Output

2 2
 
 
 
#include<stdio.h>
#include<string.h>
#include<stdlib.h>

#define maxn 120

char str[maxn][maxn];
char source[maxn];

int n;
void Input()
{
  int i, len = 1000;
  
  scanf("%d", &n);
  
  source[0] = '';
  
  for(i = 0; i < n; i++)
  {
    scanf("%s", str[i]);
    int lens = strlen(str[i]);
    if(len > lens)
    {
      strcpy(source, str[i]);
      len = lens;
    }
  }
}

int Find(char substrs[], char revsubstr[])
{
  for(int i = 0; i < n; i++)
  {
    if(strstr(str[i], substrs) == 0 && strstr(str[i], revsubstr) == 0)
      return 0;
  }
  return 1;
}

int substring()
{
  int i, j, len = strlen(source);
  
  for(i = len; i > 0; i--)
    for(j = 0; j + i <= len; j++)
    {
      char substrs[maxn] = {0}, revsubstr[maxn];
      
      strncpy(substrs, source+j, i);
      strcpy(revsubstr, substrs);
      strrev(revsubstr);
      if(Find(substrs, revsubstr))
        return i;
    }
    return 0;
}

int main()
{
  int t;
  
  scanf("%d", &t);
  
  while(t--)
  {
    Input();
    
    printf("%d
", substring());
  }
  return 0;
}
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原文地址:https://www.cnblogs.com/Tinamei/p/4234749.html