tmp-动态规划-迷宫走法

https://www.cnblogs.com/Kobe10/p/6357526.html

#include <iostream> using namespace std; //dp[i][j] = dp[i-1][j] + dp[i][j-1]; int get_steps_num(int* a, int m; int n) { if (a==nullptr || m<=0 || n<=0) { return -1; } int dp[m][n]; for (int i=0; i<m; i++) for(int j=0; j<n; j++) { d[i][j] = 1; } if (m == 1) { return 1; } if (n == 1) { return 1; } for (int i=1; i<m; i++) for(int j=1; j<n; j++) { dp[i][j] = dp[i-1][j] + dp[i][j-1]; } return dp[m-1][n-1]; } int main() { //int a; //cin >> a; int res = get_steps_num(); }
原文地址:https://www.cnblogs.com/TMatrix52/p/12606133.html