Leetcode13. 罗马数字转整数

class Solution:
    def romanToInt(self, s: str) -> int:

        Roman= ['I','V','X','L','C','D','M']        
        Int = [1,5,10,50,100,500,1000]
        s1= 0
        i=0
        while i<len(s):
            if i==len(s)-1:
                s1+= Int[Roman.index(s[i])]
                break
            elif s[i]!=s[i+1] and Roman.index(s[i])<Roman.index(s[i+1]):
                s1+= (Int[Roman.index(s[i+1])]-Int[Roman.index(s[i])])
                i+=2
            else:
                s1+=Int[Roman.index(s[i])]
                i+=1

        return s1