LeetCode --- Pascal's Triangle

题目链接

杨辉三角

附上代码:

 1 class Solution {
 2 public:
 3     vector<vector<int> > generate(int numRows) {
 4         vector<vector<int> > ans(numRows);
 5         for (int i = 0; i < numRows; i++) {
 6             ans[i].push_back(1);
 7             for (int j = 1; j < i; j++) {
 8                 ans[i].push_back(ans[i-1][j-1] + ans[i-1][j]);
 9             }
10             if (i > 0) {
11                 ans[i].push_back(1);
12             }
13         }
14         
15         return ans;
16     }
17 };
原文地址:https://www.cnblogs.com/Stomach-ache/p/3715769.html