HDU 3415 单调队列

 1 #include<stdio.h>
 2 #include<string.h>
 3 #include<queue>
 4 using namespace std;
 5 #define max 100000+10
 6 
 7 int a[max],sum[(max<<1)],ans;
 8 int h,t,n,k;
 9 deque<int> q;
10 
11 void inq(int i){
12     while(!q.empty()&&sum[i]<sum[q.back()]){
13         q.pop_back();
14     }
15     q.push_back(i);
16 }
17 
18 void outq(){
19     while(!q.empty()&&q.back()-q.front()>=k){
20         q.pop_front();
21     }
22 }
23 
24 int main(){
25     int m;
26     scanf("%d",&m);
27     while(m--){
28         q.clear();
29         scanf("%d%d",&n,&k);
30         sum[0]=0;
31         for(int i=1;i<=n;i++){
32             scanf("%d",&a[i]);
33             sum[i]=sum[i-1]+a[i];
34         }
35         for(int i=n+1;i<=n+k;i++){
36             sum[i]=sum[i-1]+a[i-n];
37         }
38             ans=-999999999;
39         int st,end;
40         //q[++t]=0;
41         for(int i=1;i<n+k;i++){
42             inq(i-1);
43             outq();
44             int res=sum[i]-sum[q.front()];
45             if(ans<res){
46                 ans=res;
47                 st=q.front()+1;
48                 end=i;
49             }
50         }
51         if(st>n){
52             st-=n;
53         }
54         if(end>n){
55             end-=n;
56         }
57         printf("%d %d %d
",ans,st,end);
58     }
59 }
原文地址:https://www.cnblogs.com/Stomach-ache/p/3703217.html