POJ 2311 博弈

 1 #include<stdio.h>
 2 #include<string.h>
 3 #include<set>
 4 using namespace std;
 5 
 6 int sg[205][205];
 7 
 8 int solve(int w,int h){
 9     if(sg[w][h]!=-1){
10         return sg[w][h];
11     }
12     set<int> my_set;
13     for(int i=2;w-i>=2;i++){
14         my_set.insert(solve(i,h)^solve(w-i,h));
15     }
16     for(int j=2;h-j>=2;j++){
17         my_set.insert(solve(w,j)^solve(w,h-j));
18     }
19     int g=0;
20     while(my_set.count(g)){
21         g++;
22     }
23     return sg[w][h]=g;
24 }
25 
26 int main(){
27     int w,h;
28     memset(sg,-1,sizeof(sg));
29     while(~scanf("%d%d",&w,&h)){
30         if(solve(w,h)){
31             puts("WIN");
32         }
33         else{
34             puts("LOSE");
35         }
36     }
37 }


原文地址:https://www.cnblogs.com/Stomach-ache/p/3703194.html