BZOJ 4236 set乱搞

思路:
取个差 在set里面找 更新
(这个用map更好吧 但是我不会……)

//By SiriusRen
#include <set> 
#include <cstdio>
#include <algorithm>
using namespace std;
int n,sum[200050][3],ans;
char ch[200050];
struct Node{int x,y,rec;}jy;
struct cmp{
    bool operator ()(Node a,Node b){
        if(a.x==b.x)return a.y<b.y;
        return a.x<b.x;
    } 
};
set<Node,cmp>s;
set<Node,cmp>::iterator it;
int main(){
    scanf("%d%s",&n,ch+1);
    s.insert(jy);
    for(int i=1;i<=n;i++){
        sum[i][0]=sum[i-1][0]+(ch[i]=='J');
        sum[i][1]=sum[i-1][1]+(ch[i]=='O');
        sum[i][2]=sum[i-1][2]+(ch[i]=='I');
        jy.x=sum[i][1]-sum[i][0],jy.y=sum[i][2]-sum[i][1];
        jy.rec=i,it=s.find(jy);
        if(it==s.end())s.insert(jy);
        else ans=max(ans,i-it->rec);
    }
    printf("%d
",ans);
}

这里写图片描述

原文地址:https://www.cnblogs.com/SiriusRen/p/6532237.html