uva10879 Code Refactoring

AC如此简单,只要用心做,没什么不可以

View Code
#include<stdio.h>
int main()
{
    int T, k, f[4], top, j;
    scanf("%d",&T);
    for(int i = 0;i < T; i++)
    {
        top = 0;
        scanf("%d",&k);
        for(j = 2;;j++)
            if(k%j == 0)
                break;
        f[0] = j;f[1] = k/j;
        j++;
        for(;;j++)
            if(k%j == 0)
                break;
        f[2] = j;f[3] = k/j;
        printf("Case #%d: %d = %d * %d = %d * %d\n",i+1,k,f[0],f[1],f[2],f[3]);
    }
    return 0;
}
原文地址:https://www.cnblogs.com/SDUTYST/p/2619429.html