uva424 Integer Inquiry

简单的数组应用,比150!容易多了,不用什么算法

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 1 #include<stdio.h>
 2 #include<string.h>
 3 int num[200] = {0}, top = 0;
 4 int main()
 5 {
 6     char st[102];
 7     int len, i;
 8     while(gets(st) && st[0] != '0')
 9     {
10         len = strlen(st);
11         if(top < len) top = len;
12         for(i = 0;i < len; i++)
13         {
14             num[i] += st[len-i-1]-'0';
15         }
16     }
17     for(i = 0;i < top; i++)
18     {
19         num[i+1] += num[i]/10;
20         num[i] %= 10;
21     }
22     while(num[top] != 0)
23     {
24         num[top+1] += num[top]/10;
25         num[top] %= 10;
26         top++;
27     }
28     for(i = top-1;i >= 0; i--)
29     printf("%d",num[i]);
30     printf("\n");
31     return 0;
32 }
原文地址:https://www.cnblogs.com/SDUTYST/p/2528692.html