PTA 乙级 1056 组合数的和 (15分) C/C++

 1 #include<iostream>
 2 
 3 using namespace std;
 4 
 5 int main() {
 6     int n = 0;
 7     int num[10] = { 0 };
 8     int sum = 0;
 9     cin >> n;
10     for (int i = 0; i < n; ++i)cin >> num[i];
11     for (int i = 0; i < n; i++) {
12         for (int j = i + 1; j < n; ++j) {
13             if (num[i] != 0) sum += num[i] * 10 + num[j]; //保证十位不为零
14             if (num[j] != 0) sum += num[j] * 10 + num[i];
15         }
16     }
17     cout << sum;
18     return 0;
19 }

今天水水水！

默默地一点点变强，细节决定成败