KMP POJ 1961 Period

题目传送门

 1 /*
 2     题意:求一个串重复出现(>1)的位置
 3     KMP:这简直和POJ_2406没啥区别
 4 */
 5 /************************************************
 6 * Author        :Running_Time
 7 * Created Time  :2015-8-10 9:13:24
 8 * File Name     :POJ_1961.cpp
 9  ************************************************/
10 
11 #include <cstdio>
12 #include <algorithm>
13 #include <iostream>
14 #include <sstream>
15 #include <cstring>
16 #include <cmath>
17 #include <string>
18 #include <vector>
19 #include <queue>
20 #include <deque>
21 #include <stack>
22 #include <list>
23 #include <map>
24 #include <set>
25 #include <bitset>
26 #include <cstdlib>
27 #include <ctime>
28 using namespace std;
29 
30 #define lson l, mid, rt << 1
31 #define rson mid + 1, r, rt << 1 | 1
32 typedef long long ll;
33 const int MAXN = 1e6 + 10;
34 const int INF = 0x3f3f3f3f;
35 const int MOD = 1e9 + 7;
36 int n;
37 int nex[MAXN];
38 char str[MAXN];
39 
40 
41 void get_nex(void)  {
42     int i = 0, j = -1;  nex[0] = -1;
43     while (i < n)   {
44         if (j == -1 || str[j] == str[i])    {
45             j++;    i++;
46             if (i % (i - j) == 0 && i / (i - j) > 1)    {
47                 printf ("%d %d
", i, i / (i - j));
48             }
49             nex[i] = j;
50         }
51         else    j = nex[j];
52     }
53 }
54 
55 int main(void)    {     //POJ 1961 Period
56     int cas = 0;
57     while (scanf ("%d", &n) == 1)   {
58         if (!n) break;
59         scanf ("%s", &str);
60         printf ("Test case #%d
", ++cas);
61         get_nex ();
62         puts ("");
63     }
64 
65     return 0;
66 }
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原文地址:https://www.cnblogs.com/Running-Time/p/4717794.html