HDU(1517)A Multiplication Game(博弈)

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1517

题意:2 个人玩游戏,从 1 开始,轮流对数进行累乘,直到超过一个指定的值。

[2,9] Stan wins.

[10,18] Ollie wins.

[19,162] Stan wins.

[162,324]Ollie wins.

...

...

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <algorithm>
#include <math.h>
#include <stdlib.h>
#include <queue>
#include <vector>
using namespace std;

int main (){
    double n;
    while (cin>>n){
        while(n>18) n/=18;
        //cout<<n<<endl;
        if (n>9)
            printf("Ollie wins.\n");
        else
            printf("Stan wins.\n");
    }
    return 0;
}
原文地址:https://www.cnblogs.com/Roly/p/3079837.html