Problem A

题意:

已知 (a_1)(a_k) ,推导公式见题面。

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
ll n, k, _, a;
int main() {
	//freopen("in.txt", "r", stdin);
	ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0);
	cin >> _; while (_--) {
		cin >> n >> k;
		k--;
		while (k--) {
			a = n;
			ll l = 10, r = 0;
			while (a) {
				l = min(l, a % 10);
				r = max(r, a % 10);
				a /= 10;
			}
			if (!l)break;//如果存在前导0直接break
			n += l * r;
		}
		cout << n << endl;
	}
}

The desire of his soul is the prophecy of his fate
你灵魂的欲望,是你命运的先知。

原文地址:https://www.cnblogs.com/RioTian/p/13658214.html