PAT Basic Level 1021

AC代码
 1 #include <stdio.h>
 2 #include <string.h>
 3 int main ()
 4 {
 5     char input[1001];
 6     scanf("%s",&input);
 7     int length = strlen(input);
 8     int list[10] = {0};
 9     int i;
10     for(i = 0;i < length;i++)
11     {
12         switch(input[i])
13         {
14             case '0':list['0' - '0']++;
15             break;
16             case '1':list['1' - '0']++;
17             break;
18             case '2':list['2' - '0']++;
19             break;
20             case '3':list['3' - '0']++;
21             break;
22             case '4':list['4' - '0']++;
23             break;
24             case '5':list['5' - '0']++;
25             break;
26             case '6':list['6' - '0']++;
27             break;
28             case '7':list['7' - '0']++;
29             break;
30             case '8':list['8' - '0']++;
31             break;
32             case '9':list['9' - '0']++;
33             break;
34             
35         }
36      }
37      for(i = 0;i < 10;i++)
38      {
39          if(list[i] != 0)
40          {
41              printf("%d:%d
",i,list[i]);
42          }
43       } 
44 }