连通性1 求无向图的low值

这是 DFS 系列的第一篇 。

首先给出一个重要的定理。该定理来自《算法导论》。

An undirected graph may entail some ambiguity in how we classify edges, since $(u,v)$ and $(v,u)$ are really the same edge. In such a case, we classify the edge according to whichever of $(u,v)$ or $(v,u)$ the search encounters first.

Introduction to Algorithm 3rd edition p.610

Theorem 22.10
In a depth-first search of an undirected graph $G$, every edge of $G$ is either a tree edge or a back edge.

Proof  Let $(u, v)$ be an arbitrary edge of $G$, and suppose without loss of generality that $u.d < v.d$. Then the search must discover and finish $v$ before it finishes $u$ (while $u$ is gray), since $v$ is on $u$’s adjacency list. If the first time that the search explores edge $(u, v)$, it is in the direction from $u$ to $v$, then $v$ is undiscovered (white) until that time, for otherwise the search would have explored this edge already in the direction from $v$ to $u$. Thus, $(u, v)$ becomes a tree edge. If the search explores $(u, v)$ first in the direction from $v$ to $u$, then $(u, v)$ is a back edge, since $u$ is still gray at the time the edge is first explored.

low 值大概是 Robert Tarjan 在论文 Depth-first search and linear graph algorithms  SIAM J. Comput. Vol. 1, No. 2, June 1972 给出的概念。

(p.150)"..., LOWPT(v) is the smallest vertex reachable from v by traversing zero or more tree arcs followed by at most one frond."

代码如下

 1 #define set0(a) memset(a, 0, sizeof(a))
 2 typedef vector<int> vi;
 3 vi G[MAX_N];
 4 int ts; //time stamp
 5 int dfn[MAX_N], low[MAX_N];
 6 void dfs(int u, int f){
 7     dfn[u]=low[u]=++ts;
 8     for(int i=0; i<G[u].size(); i++){
 9         int &v=G[u][i];
10         if(!dfn[v]){    //tree edge
11             dfs(v, u);
12             low[u]=min(low[u], low[v]);
13         }
14         else if(dfn[v]<dfn[u]&&v!=f){    //back edge
15             low[u]=min(low[u], dfn[v]);
16         }
17     }
18 }
19 void solve(int N){
20     set0(dfn);
21     ts=0;
22     for(int i=1; i<=N; i++)
23         if(!dfn[i]) dfs(i, i);
24 }
原文地址:https://www.cnblogs.com/Patt/p/4659935.html