HDU-2255 奔小康赚大钱

KM模版题。

#include <cstdlib>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <fstream>
#include <iostream>
#define rep(i, l, r) for(int i=l; i<=r; i++)
#define N 345
#define clr(x, c) memset(x, c, sizeof(x));
#define ll long long
#define MAX 1<<30
using namespace std;
int read()
{
	int x=0, f=1; char ch=getchar();
	while (ch<'0' || ch>'9') { if (ch=='-') f=-1; ch=getchar(); }
	while (ch>='0' && ch<='9') { x=x*10+ch-'0'; ch=getchar(); }
	return x*f;
}
int n, nx, ny, lx[N], ly[N], v[N][N], l[N], st[N];
bool vx[N], vy[N];

bool Find(int x)
{
	vx[x]=1;
	rep(y, 1, ny) if (!vy[y])
	{
		int a=lx[x]+ly[y]-v[x][y];
		if (!a) 
		{
			vy[y]=1; 
			if (!l[y] || Find(l[y])) { l[y]=x; return true; }
		}
		else st[y]=min(st[y], a);
	}
	return false;
}

int KM()
{
	rep(i, 1, nx) lx[i]=-MAX; clr(ly, 0); clr(l, 0);
	rep(i, 1, nx) rep(j, 1, ny) if (lx[i]<v[i][j]) lx[i]=v[i][j];
	rep(i, 1, nx) 
	{
		rep(j, 1, ny) st[j]=MAX;
		while (1)
		{
			clr(vx, 0); clr(vy, 0);
			if (Find(i)) break;
			int a=MAX; rep(j, 1, ny) if (!vy[j] && a>st[j]) a=st[j];
			rep(j, 1, nx) if (vx[j]) lx[j]-=a;
			rep(j, 1, ny) if (vy[j]) ly[j]+=a; else st[j]-=a;
		}
	}
	int ans=0;
	rep(i, 1, nx) if (l[i]) ans+=v[l[i]][i];
	return ans;
}

int main()
{
	while (~scanf("%d", &n))
	{
		nx=ny=n;
		rep(i, 1, nx) rep(j, 1, ny) v[i][j]=read();
		printf("%d
", KM());
	}
	return 0;
}

  

原文地址:https://www.cnblogs.com/NanoApe/p/4382046.html