计算方法 | Jacobi迭代法求线性方程组

很简单，类似简单迭代法。

 1 import numpy as np
 2 # Jacobi迭代法
 3 # 测试数据 增广矩阵
 4 data = [[10,-1,-2, 7.2], [-1,10,-2,8.3], [-1,-1,5, 4.2]]
 5 print(np.array(data))
 6 # 取初始值为0,0,0
 7 x = [[0] for i in range(len(data))]
 8 _x = [[0] for i in range(len(data))]
 9 print(np.array(x))
10 # 开始迭代
11 print("开始迭代：")
12 for n in range(10):
13     print("round{}:".format(n))
14     for i in range(len(data)):
15         _sum = data[i][-1] / data[i][i]
16         for j in range(len(data[0])-1):
17             if i != j:
18                 _sum -= (data[i][j] / data[i][i]) * x[j][0] # 用-=来移项
19         _x[i][0] = _sum
20     for i in range(len(x)):
21         x[i][0] = _x[i][0]
22     print(x)

over。