Leetcode刷题记录[java]——561 Array Partition I

一、前言

二、题561 Array Partition I

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

  Input: [1,4,3,2]

  Output: 4
  Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).

Note:

  1. n is a positive integer, which is in the range of [1, 10000].
  2. All the integers in the array will be in the range of [-10000, 10000].

三、解题思路

 1 class Solution {
 2     public int arrayPairSum(int[] nums) {
 3         Arrays.sort(nums);
 4         int result = 0;
 5         for (int i = 0; i < nums.length; i += 2) {
 6             result += nums[i];
 7         }
 8         return result;    
 9     }
10 }
原文地址:https://www.cnblogs.com/Myoungs/p/7832870.html