实训第四天

实训第四天了,最近脑子里灌的东西比较多,现在终于感到脑子不够用了,脑子疼啊。

今天学的依旧是mysql,学的是查询,查询命令单个简答,两个条件三个条件一组合,哎呀我的脑容量直接感觉不够用了,差点哭晕在厕所

查询条件

(1)简单查询

select * from Info

select Code as '代号',Name as '姓名' from Info as a

(2) 条件查询

 Where后面跟条件  条件要写清楚

查询成绩表中成绩(degree)为92的信息

Select * from score where degree =”92”;

查询成绩表中课程号是3-245并且成绩是86的信息

Select * from score where cno='3-245' and degree=”86”

 或者用or  并且用and

(3) 模糊查询 like  not like

查找老师表中姓李的 名字是两个字老师

select * from teacher

 where tName like '%%'  

%代表任意多个字符  _代表一个字符

(4)排序查询 order by 字段 排序值(desc降序/asc升序 )

  select * from student order by class asc

(5)范围查询 关系运算符  between。。。and

select * from Car where Price>=40 and Price<=60

select * from Car where Price between 40 and 50

(6)离散查询 in   not in

select * from student where sname in ('张三','李四')

。。。where sname =“张三” or  sname =“李四”

(7)聚合函数,统计查询

select sum(Price) from Car #查询所有价格之和 sum()求和

select count(Code) from Car #查询数据条数

select max(Code) from Car #求最大值

select min(Brand) from Car #求最小值

select avg(Price) from Car #求平均值

(8)分页查询 limit 从第几条开始,取多少条数据

#每页显示5条数据,取第2页的数据

select * from student limit (pageSize-1)*5,5

注:Where 后面不能接limit,表示为空

select * from student limit (n-1)*5,5

select * from student limit 5 只写一个5时,表示默认从第0条开始

(9)去重查询distinct

select distinct cno from score;

(10)分组查询 group by 字段  having 条件

select count(*),cno,group_concat(degree),sum(degree) from score group by cno ;

select cno,group_concat(degree),sum(degree) from score group by cno having count(*)>3

#分组之后根据条件查询使用having 不使用where

根据某个字段分组

Having相当于where

Select count(*),cno,group_concat(sno)

高级查询

  1. 连接查询,对列的扩展

   Select * from student as stu,score as sc

where stu.sno = sc.sno and sc.sno = “103” ;

连接查询Join 表名on条件

Select * from teacher

Join course

On+条件(on teacher.tno = course.tno

Join score

On(on course.cno = score.cno)

2.联合查询,对行的扩展

    select Code,Name from Info

    union

    select Code,Name from Nation

不相同条件不能连接,必须的一一对应的查询条件

3.子查询

(1)无关子查询

查询老师的信息,根据老师的编号

Select * from teacher where tno =?

查询教计算机的老师的编号

Select tno from course where cname = “计算机导论”;

合并

select * fron teacher where tno =Select tno from course where cname = “计算机导论”

;

以上是所学内容,还是需要多练啊

原文地址:https://www.cnblogs.com/MylesXxx/p/7780192.html