HDU 1698

线段树,懒惰标记

 1 #include <cstdio>
 2 #include <iostream>
 3 using namespace std;
 4 #define N 400010
 5 int sum[N],lazy[N];
 6 void pushup(int root){
 7     sum[root]=sum[root*2]+sum[root*2+1];
 8 }
 9 void pushdown(int root,int x){
10     if(lazy[root] != -1) {
11         lazy[root*2] = lazy[root*2+1] = lazy[root];
12         sum[root*2]=(x-x/2)*lazy[root];
13         sum[root*2+1]=x/2*lazy[root];
14         lazy[root]=-1;
15     }
16 }
17 void build(int l,int r,int root){
18     lazy[root]=-1,sum[root]=1;
19     if(l==r)return ;
20     int mid=(l+r)/2;
21     build(l,mid,root*2);
22     build(mid+1,r,root*2+1);
23     pushup(root);
24 }
25 
26 void query(int x,int y,int l,int r,int root,int a){
27     if(x<=l&&y>=r){
28         lazy[root] = a;
29          sum[root] = a*(r-l+1);
30          return;
31     }
32     pushdown(root,r-l+1);
33     int mid=(r+l)/2;
34     if(x<=mid)query(x,y,l,mid,root*2,a);
35     if(y>mid)query(x,y,mid+1,r,root*2+1,a);
36     pushup(root);
37 }
38 int main(){
39     //freopen("test.txt","r",stdin);
40     int t,n,q,x,y,z,case1=0;
41     scanf("%d",&t);
42     while(t--){
43         case1++;
44         scanf("%d%d",&n,&q);
45         build(1,n,1);
46         for(int i=0;i<q;i++){
47             scanf("%d%d%d",&x,&y,&z);
48             query(x,y,1,n,1,z);
49         }
50         printf("Case %d: The total value of the hook is %d.
",case1,sum[1]);
51     }
52     return 0;
53 }



原文地址:https://www.cnblogs.com/Mr-Xu-JH/p/3880600.html