hdu 2063 过山车

http://acm.hdu.edu.cn/showproblem.php?pid=2063

View Code
 1 #include <cstdio>
 2 #include <vector>
 3 #include <cstring>
 4 
 5 using namespace std;
 6 
 7 const int maxn = 501;
 8 vector<int> p[maxn];
 9 int mat[maxn];
10 bool vis[maxn];
11 
12 bool dfs(int v){
13     for (int i = 0; i < p[v].size(); i++){
14         int t = p[v][i];
15 
16         if (!vis[t]){
17             vis[t] = true;
18             if (mat[t] == -1 || dfs(mat[t])){
19                 mat[t] = v;
20                 return true;
21             }
22         }
23     }
24     return false;
25 }
26 
27 int match(int m, int n){
28     int cnt = 0;
29 
30     memset(mat, -1, sizeof(mat));
31     for (int i = 1; i <= m; i++){
32         memset(vis, false, sizeof(vis));
33         if (dfs(i)) cnt++;
34     }
35 
36     return cnt;
37 }
38 
39 bool deal(){
40     int k, m, n;
41     int a, b;
42 
43     scanf("%d", &k);
44     if (!k) return false;
45     scanf("%d%d", &m, &n);
46     for (int i = 1; i <= m; i++) p[i].clear();
47     for (int i = 0; i < k; i++){
48         scanf("%d%d", &a, &b);
49         p[a].push_back(b);
50     }
51     printf("%d\n", match(m, n));
52 
53     return true;
54 }
55 
56 int main(){
57     #ifndef ONLINE_JUDGE
58     freopen("in", "r", stdin);
59     #endif
60     while (deal());
61 
62     return 0;
63 }

(代码更新了,之前不懂原理,搞了个相对复杂的,现在修改成较为简单的一个)

  切一下水题,试一下简单的二分匹配,1y了~  向大牛学习,学习各种知识,各种技巧!

  keep walking...我一定要不负众望,向高峰迈进!

——written by Lyon

原文地址:https://www.cnblogs.com/LyonLys/p/hdu_2063_Lyon.html