A1005

输出输入的n位整数的每一位之和的英文,注意一下输出的数组嵌套。

 1 #include<cstdio>
 2 #include<iostream>
 3 using namespace std;
 4 int main(){
 5     string num[10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
 6     string input;
 7     cin>>input;
 8     long long sum=0,dig[1000];
 9     int len=input.length();
10     for(int i=0;i<len;i++) sum+=input[i]-'0';
11     int con=0;
12     while(sum!=0){
13         dig[con]=sum%10;
14         sum=sum/10;
15         con+=1;
16     }
17     cout<<num[dig[con-1]];
18     for(int i=con-2;i>=0;i--){
19         cout<<' '<<num[dig[i]];
20     }
21     return 0;
22 }
原文地址:https://www.cnblogs.com/Lynn-2019/p/12113478.html