sgu488

http://acm.sgu.ru/problem.php?contest=0&problem=488

#include<iostream>
#include<math.h>
using namespace std;

int T , N;
int a[100000] ={0};
int b[100000] ={0};
int L[100000] ={0};
int R[100000] ={0};
int search(int a[],int n)
{
	int t;

	for(t = 1 ; t < n; t++)
	{
		if(a[t] < a[t-1])
			L[t] = L[t -1];
		else
			L[t] = t;
	}
	R[n-1] = n-1;
	for(t =n-1; t> 0; t--)
	{
		if(a[t-1] < a[t])
			R[t-1] =R[t];
		else
			R[t-1] = t-1;
	}
	int ans = 0;
	for(t =0; t < n; t++)
	{
		ans =max(min(t-L[t],R[t]-t),ans);
	}
	return ans;
}
int main()
{
	cin >> T ;
   //input the number 
	while(T--)
	{
		cin >> N;
		for(int i= 0; i< N;i++)
			cin>>a[i];
		for(int i = 0; i < N; i++)
			b[i] = -a[i];
		cout << search(b, N) << " " << search(a, N) << endl;
	}
	return 0;
}

  

原文地址:https://www.cnblogs.com/LyningCoder/p/3714976.html