平衡二叉树的旋转(左旋和右旋)

右旋:

void RightSpin(Tree** ppTree)
{
    Tree* pTree = *ppTree;
    Tree* ptmp = pTree->pleft;
    pTree->pleft = ptmp->pright;
    if(ptmp->pright)
        ptmp->pright->pFather = pTree;
    ptmp->pright = pTree;
    ptmp->pFather = pTree->pFather;
    if(pTree->pFather)
    {printf("----
");

        if(pTree == pTree->pFather->pright)
            pTree->pFather->pright = ptmp;
        else
            pTree->pFather->pleft = ptmp;
    }
    else

        *ppTree = ptmp;
    pTree->pFather = ptmp;
}

左旋:

void LeftSpin(Tree** ppTree)
{
    Tree* pTree = *ppTree;
    Tree* ptmp = pTree->pright;
    pTree->pright = ptmp->pleft;
    if(ptmp->pleft)
        ptmp->pleft->pFather = pTree;
    ptmp->pleft = pTree;
    ptmp->pFather = pTree->pFather;
    if(pTree->pFather)
    {
        if(pTree == pTree->pFather->pright)
            pTree->pFather->pright = ptmp;
        else
            pTree->pFather->pleft = ptmp;
    }
    else
        *ppTree = ptmp;
    pTree->pFather = ptmp;
}

感谢某人的debug:ptmp->pFather  指针,无论pTree是否有根节点都要 = pTree->pFather;(没有是赋为空)

原文地址:https://www.cnblogs.com/Lune-Qiu/p/9045665.html