排序二叉树转变为有序双向链表

要点:

1.直接改变树的结构

2.排序二叉树在中序遍历的时候是有序的

3.双向链表,需要前后两个指针(可以将Tree的节点作为链表节点)

代码实现:中序的递归实现

void ToList(Tree* pTree ,Tree** pHead,Tree** pEnd )
{
    if(pTree == NULL ) return;
    ToList(pTree->pleft,pHead,pEnd);
    if(*pHead == NULL)
    {
        *pHead = pTree;
        *pEnd = pTree;
    }
    else
    {
        (*pEnd)->pright = pTree;
        pTree->pleft = *pEnd;
    }
    (*pEnd) = pTree;
    ToList(pTree->pright,pHead,pEnd);
}
原文地址:https://www.cnblogs.com/Lune-Qiu/p/9038574.html