leetcode Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5

简单题,不过我刚开始少想了一种情况,就是“hello world      ”后面有很多空格,但是最后一个单词还是world

所以我们要从第一个不是空格的字符开始判断,然后再到下一个空格停止。

 1 class Solution {
 2 public:
 3     int lengthOfLastWord(string s) {
 4         if(s=="") return 0;
 5         int len=s.length();
 6         int i=len-1;
 7         int count=0;
 8 
 9         while(s[i]==' ') i--;
10         for(;i>=0;i--)
11         {
12             if(s[i]!=' ') count++;
13             else break;
14         }
15         return count;
16     }
17 };
原文地址:https://www.cnblogs.com/LUO77/p/5038004.html