leetcode Merge Sorted Array

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.

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一直没有理解题意，意思是把num2插入到nums1中，但是nums1保持m个元素，nums2保持n个元素。

后来发现只要先保持nums1 n个元素，然后把nums2插进去，然后排序就好了，我这样做算是作弊吗？

class Solution {
public:
    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
        for(int i=0;i<n;i++){
            nums1[m++]=nums2[i];
        }
        sort(nums1.begin(),nums1.end());
        
    }
};

 看看大神的做法：

class Solution {
public:
    void merge(int A[], int m, int B[], int n) {
        int temp[m+n];
        int i = 0, j = 0, t = 0;
        while(i < m && j < n)
        {
            if(A[i] < B[j])
                temp[t++] = A[i++];
            else
                temp[t++] = B[j++];
        }
        while(i < m)
            temp[t++] = A[i++];
        while(j < n)
            temp[t++] = B[j++];
        while(--t >= 0)
            A[t] = temp[t];
    }
};