hdu 2544 最短路

题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=2544

简单最短路问题

#include<stdio.h>
#define INF 1<<30
int n,m,map[105][105],dis[105];
bool bellman_ford(int start,int end)
{
    int i,j,k;
    for(i = 1; i <= n; i++)
        dis[i] = INF;
    dis[start] = 0;
    for(k = 1; k <= n; k++)
    {
        for(i = 1; i <= n; i++)
        {
            for(j = 1 ; j <= n; j++)
            {
                if(map[i][j] < INF && dis[j] > dis[i] + map[i][j])
                    dis[j] = dis[i] + map[i][j];
            }        
        }
    }
    for(i = 1; i <= n; i++)
    {
        for(j = 1; j <= n; j++)
            if(map[i][j] < INF && dis[j] > dis[i] + map[i][j])
                return false;
    }
    return true;
}
int main()
{
    int i,j,a,b,c;
    while(~scanf("%d%d",&n,&m) && (n||m))
    {
        for(i = 1; i <= n; i++)
            for(j = 1; j <= n; j++)
                map[i][j] = (i == j ? 0 : INF);
            while(m--)
            {
                scanf("%d%d%d",&a,&b,&c);
                map[a][b] = map[b][a] = c;
            }
            bellman_ford(1,n);
            printf("%d\n",dis[n]);
    }
    return 0;
}


原文地址:https://www.cnblogs.com/LUO257316/p/3220857.html