CODEVS 1080 (单点更新+区间查询)

题目链接:http://codevs.cn/problem/1080/

#include <cstdio>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <queue>
#include <vector>
#include <cstring>
#include <map>
#define mem(a) memset(a,0,sizeof(a))
using namespace std;
typedef long long lll;
const int maxn = 4000005;
const lll INF = 0x3f3f3f3f3f;
int dir[8][2]= {0,1,1,0,0,-1,-1,0,1,-1,-1,-1,1,1,-1,1};
int dir2[4][2]= {0,1,0,-1,1,0,-1,0};
bool flag;
int a[maxn],sum[maxn],n,ans,num[maxn],b[maxn];
void pushup(int k)
{
    sum[k] = sum[k*2] + sum[k*2+1];
}
void build(int k,int l,int r)//递归建树
{
    if(l == r)
    {
        sum[k] = a[l];
        return ;
    }
    else
    {
        int mid = (l+r) / 2;
        build(k<<1,l,mid);
        build(k*2+1,mid+1,r);
        pushup(k);
    }
}
void update(int l,int r,int L,int R,int k,int v)//单点更新
{
    if(L == l && R == r)
    {
        sum[k] += v;
        return ;
    }
    else
    {
        int mid = (L + R) / 2;
        if(l <= mid) update(l,r,L,mid,k*2,v);
        if(mid < r) update(l,r,mid+1,R,k*2+1,v);
        pushup(k);
    }
}
void Search(int l,int r,int L,int R,int k)//区间查询
{
    if(L >= l&& R <= r)
    {
        ans += sum[k];
        return;
    }
    int mid = (L + R) / 2;
    if(mid >= l)  Search(l,r,L,mid,k*2);
    if(mid < r)  Search(l,r,mid+1,R,k*2+1);
}
int main()
{
    int m;
    cin >> n;
    for(int i = 1; i <= n; i++)
    {
        cin >> a[i];
    }
    mem(sum);
    build(1,1,n);//建树
    int z,x,c;
    cin >> m;
    for(int i = 1; i <= m; i++)
    {
        cin >> z >> x >> c;
        if(z == 1)
            update(x,x,1,n,1,c);
        else
        {
            ans = 0;
           Search(x,c,1,n,1);
           cout << ans << endl;
        }
    }
    return 0;
}
原文地址:https://www.cnblogs.com/LLLAIH/p/11321763.html