P1505 [国家集训队]旅游

题目链接

这道题其实还是比较好想的,同样是边权问题。我们需要维护最大值,最小值,和。最坑的地方就是路径上的所有数变相反数,其实这个就是把区间和*-1,区间最大*-1,区间最小*-1,最后pushdown的时候将取反标记^1,接下来一系列都是常规操作。而这里还要记住,单点修改时也要下传lazy标记。而我在跳链的时候写错了调了很久,样例非常之水。

代码,又臭又长,bzoj上都还AC不了

#include<bits/stdc++.h>
using namespace std;
const int maxn=3e6+7;
struct node{
    int l,r,sum,mx,lazy1,mi;
}tree[maxn*6];
struct node1{
    int nxt,from,to,val;
}edge[maxn*4];
int head[maxn],cnt;
int x,y,v,n,m;
char opt[666];
void add(int x,int y,int v){
    edge[++cnt].nxt=head[x];
    edge[cnt].from=x;
    edge[cnt].to=y;
    edge[cnt].val=v;
    head[x]=cnt;
}
int ljb[maxn],dep[maxn],son[maxn],fa[maxn],size[maxn],top[maxn],w[maxn],rev[maxn],id[maxn],Time;
void dfs1(int x,int f){
    dep[x]=dep[f]+1;
    fa[x]=f;
    size[x]=1;
    int maxson=-1;
    for(int i=head[x];i;i=edge[i].nxt){
        int go=edge[i].to;
        if(go==fa[x]) continue;
        w[go]=edge[i].val;
        dfs1(go,x);
        size[x]+=size[go];
        if(size[go]>maxson){
            maxson=size[go];
            son[x]=go;
        }
    }
}
void dfs2(int x,int topf){
    top[x]=topf;
    id[x]=++Time;
    rev[id[x]]=w[x];
    if(!son[x]) return;
    dfs2(son[x],topf);
    for(int i=head[x];i;i=edge[i].nxt){
        int go=edge[i].to;
        if(go==fa[x]||go==son[x]) continue;
        dfs2(go,go);
    }
}
void pushdown(int now){
    if(tree[now].lazy1){
        tree[now<<1].sum*=-1;
        tree[now<<1|1].sum*=-1;
        swap(tree[now<<1].mx,tree[now<<1].mi);
        tree[now<<1].mx*=-1;
        tree[now<<1].mi*=-1;
        swap(tree[now<<1|1].mx,tree[now<<1|1].mi);
        tree[now<<1|1].mx*=-1;
        tree[now<<1|1].mi*=-1;
        tree[now<<1].lazy1^=1;
        tree[now<<1|1].lazy1^=1;
        tree[now].lazy1=0;
    }
}
void pushup(int now){
    tree[now].sum=tree[now<<1].sum+tree[now<<1|1].sum;
    tree[now].mi=min(tree[now<<1].mi,tree[now<<1|1].mi);
    tree[now].mx=max(tree[now<<1].mx,tree[now<<1|1].mx);
}
void build(int now,int l,int r){
    tree[now].l=l,tree[now].r=r;
    if(l==r){
        tree[now].mi=tree[now].mx=tree[now].sum=rev[l];
        return;
    }
    int mid=(l+r)>>1;
    build(now<<1,l,mid);
    build(now<<1|1,mid+1,r);
    pushup(now);
}
void update1(int now,int x,int v){
    if(tree[now].l==tree[now].r){
        tree[now].mi=tree[now].mx=tree[now].sum=v;
        return;
    }
    pushdown(now);
    int mid=(tree[now].l+tree[now].r)>>1;
    if(x<=mid) update1(now<<1,x,v);
    else update1(now<<1|1,x,v);
    pushup(now);
}
void update2(int now,int l,int r){
    if(tree[now].l>=l&&tree[now].r<=r){
        tree[now].sum*=-1;
        tree[now].lazy1^=1;
        swap(tree[now].mi,tree[now].mx);
        tree[now].mi*=-1;
        tree[now].mx*=-1;
        return;
    }
    pushdown(now);
    int mid=(tree[now].l+tree[now].r)>>1;
    if(l<=mid) update2(now<<1,l,r);
    if(r>mid) update2(now<<1|1,l,r);
    pushup(now); 
}
void linkup(int x,int y){
    while(top[x]!=top[y]){
        if(dep[top[x]]<dep[top[y]]) swap(x,y);
        update2(1,id[top[x]],id[x]);
        x=fa[top[x]];
    }
    if(dep[x]<dep[y]) swap(x,y);
    update2(1,id[y]+1,id[x]);
}
int query1(int now,int l,int r){
    if(tree[now].l>=l&&tree[now].r<=r) return tree[now].sum;
    pushdown(now);
    int val=0;
    int mid=(tree[now].l+tree[now].r)>>1;
    if(l<=mid) val+=query1(now<<1,l,r);
    if(r>mid) val+=query1(now<<1|1,l,r);
    return val;
}
int query2(int now,int l,int r){
    if(tree[now].l>=l&&tree[now].r<=r) return tree[now].mx;
    pushdown(now);
    int mid=(tree[now].l+tree[now].r)>>1;
    int val=-0x3f3f3f3f;
    if(l<=mid) val=max(val,query2(now<<1,l,r));
    if(r>mid) val=max(val,query2(now<<1|1,l,r));
    return val;
}
int query3(int now,int l,int r){
    if(tree[now].l>=l&&tree[now].r<=r) return tree[now].mi;
    pushdown(now);
    int mid=(tree[now].l+tree[now].r)>>1;
    int val=0x3f3f3f3f;
    if(l<=mid) val=min(val,query3(now<<1,l,r));
    if(r>mid) val=min(val,query3(now<<1|1,l,r));
    return val;
}
int link1(int x,int y){
    int ans=0;
    if(x==y) return 0;
    while(top[x]!=top[y]){
        if(dep[top[x]]<dep[top[y]]) swap(x,y);
        ans+=query1(1,id[top[x]],id[x]);
        x=fa[top[x]];
    }
    if(dep[x]<dep[y]) swap(x,y);
    ans+=query1(1,id[y]+1,id[x]);
    return ans;
}
int link2(int x,int y){
    int ans=-0x3f3f3f3f;
    if(x==y) return 0;
    while(top[x]!=top[y]){
        if(dep[top[x]]<dep[top[y]]) swap(x,y);
        ans=max(ans,query2(1,id[top[x]],id[x]));
        x=fa[top[x]];
    }
    if(dep[x]<dep[y]) swap(x,y);
    ans=max(ans,query2(1,id[y]+1,id[x]));
    return ans;
}
int link3(int x,int y){
    int ans=0x3f3f3f3f;
    if(x==y) return 0;
    while(top[x]!=top[y]){
        if(dep[top[x]]<dep[top[y]]) swap(x,y);
        ans=min(ans,query3(1,id[top[x]],id[x]));
        x=fa[top[x]];
    }
    if(dep[x]<dep[y]) swap(x,y);
    ans=min(ans,query3(1,id[y]+1,id[x]));
    return ans;
}
int o,p,q;
int main(){
    scanf("%d",&n);
    for(int i=1;i<n;i++){
        scanf("%d%d%d",&x,&y,&v);
        x++;y++;
        add(x,y,v);add(y,x,v);
    }
    dfs1(1,0);
    dfs2(1,1);
    build(1,1,n);
    scanf("%d",&m);
    for(int i=1;i<=m;i++){
        scanf("%s",opt);
        if(opt[0]=='C'){
            scanf("%d%d",&o,&p);
            int st=edge[o<<1].from;
            int ed=edge[o<<1].to;
            int who=dep[st]<dep[ed]?ed:st;
            update1(1,id[who],p);
        }
        if(opt[0]=='N'){
            scanf("%d%d",&o,&p);
            o++;p++;
            linkup(o,p);
        }
        if(opt[0]=='S'){
            scanf("%d%d",&o,&p);
            o++;p++;
            printf("%d
",link1(o,p));
        }
        if(opt[1]=='A'){
            scanf("%d%d",&o,&p);
            o++;p++;
            printf("%d
",link2(o,p));
        }
        if(opt[1]=='I'){
            scanf("%d%d",&o,&p);
            o++;p++;
            printf("%d
",link3(o,p));
        }
    }
    return 0;
}
View Code
原文地址:https://www.cnblogs.com/LJB666/p/11371338.html