第二周 递归:1.SIMPLE PREFIX COMPRESSION

总时间限制:
2000ms
内存限制:
65536kB
描述
Many databases store the data in the character fields (and especially indices) using prefix compression. This technique compresses a sequence of strings A1, ..., ANby the following method: if there are strings Ai = ai,1ai,2...ai,pand Ai + 1= ai+1,1ai+1,2...ai+1,q
such that for some j <= min(p, q) ai,1= ai+1,1, ai,2= ai+1,2, ... ai,j= ai+1,j, then the second string is stored as [j]ai+1,j+1ai+1,j+2... ai+1,q, where [j] is a single character with code j.

If j = 0, that is, strings do not have any common prefix, then the second string is prefixed with zero byte, and so the total length actually increases.


Constraints
1 <= N <= 10000, 1 <= length(Ai) <= 255.
输入
First line of input contains integer number N, with following N lines containing strings A1 ... AN
输出
Output must contain a single integer -- minimal total length of compressed strings.
样例输入
3
abc
atest
atext
样例输出
11
 1 #include <iostream>
 2 #include <cstring>
 3 #include <cstdio>
 4 using namespace std;
 5 char s[10005][300];
 6 int main(int argc,const char *argv[])
 7 {
 8     int n = 0;
 9     int tep = 0;
10     scanf("%d", &n);
11     for(int i = 0; i < n ; i++)
12     {
13         scanf("%s", s[i]);
14     }
15     int sum =(int)strlen(s[0]);
16     for(int i = 1; i < n; i++)
17     {
18         for(int j = 0; j < strlen(s[i]) && j < strlen(s[i - 1]); j++)
19         {
20             if(s[i][j] == s[i - 1][j]) tep++;
21             else {sum =sum + (int)strlen(s[i]) - tep + 1; tep = 0; break;}
22         }
23         if(tep) {sum =sum + (int)strlen(s[i]) - tep + 1; tep = 0;}
24     }
25     printf("%d\n", sum);
26 } 
原文地址:https://www.cnblogs.com/Konayuki2015/p/4514235.html