卡片游戏

Description

桌上有一叠牌,从第一张牌(即位于顶面的牌)开始从上往下依次编号为1~n。当至少还剩两张牌时进行以下操作:把第一张牌扔掉,然后把新的第一张放到整叠牌的最后。输入n,输出每次扔掉的牌,以及最后剩下的牌。 

Input

第一行为一个整数t(0<t<40),表示测试用例个数。以下t行每行包含一个整数n(0<n<40),为一个测试用例的牌数。 

Output

为每个测试用例单独输出一行,该行中依次输出每次扔掉的牌以及最后剩下的牌,每张牌后跟着一个空格。

Sample Input
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2
7
4 
Sample Output
1 3 5 7 4 2 6
1 3 2 4

#include<iostream>
using namespace std;

struct Node
{
	Node* next;
	int data;
};

Node* Create(int n)
{
	Node* head = new Node;
	Node*p, *pre;
	head->next = NULL;
	pre = head;
	for (int i = 1; i<=n; i++)
	{
		p = new Node;
		p->data = i;
		p->next = NULL;
		pre->next = p;
		pre = p;
	}
	return head;
}

void Top(Node*head)
{
	Node*p = head->next;
	int top;
	top = head->next->data;
	cout << top << " ";
	head->next = head->next->next;
	delete p;
}

void Two(Node *head)
{
	Node*q = head->next;
	head->next = q->next;
	Node*p = head;
	while (p->next)
	{
		p = p->next;
	}
	p->next = q;
	q->next = NULL;
}

int main()
{
	int m;
	cin >> m;
	while (m-->0)
	{
		int n;
		cin >> n;
		Node*h = Create(n);
		while (n-- >= 2)
		{
			Top(h);
			Two(h);
		}
		cout << h->next->data << " ";
		cout << endl;
		delete h;
	}

	return 0;
}
原文地址:https://www.cnblogs.com/KennyRom/p/5908894.html