ArrayList集合-[习题]--C#

:向集合中添加10个元素,计算平均值,求最大、最小值。

 1             double sum = 0;
 2             list.AddRange(new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9 });
 3             int Max, Min;
 4             Max = Min = (int)list[0];
 5 
 6             for (int i = 0; i < list.Count; i++)
 7             {
 8                     //最大值
 9                 if(Max < (int)list[i])
10                 {
11                     Max = (int)list[i + 1];
12                 }
13                     //最小值
14                 else if (Min > (int)list[i])
15                 {
16                     Min = (int)list[i];
17                 }
18                 else { }
19                 sum += Convert.ToDouble(list[i]);
20             }
21             for (int i = 0; i < list.Count; i++)
22             {
23                 Console.Write(list[i] + " ");
24             }
25             Console.WriteLine("
Avg = {0}",sum / list.Count);
26             Console.WriteLine("Max = {0}", Max);
27             Console.WriteLine("Min = {0}", Min);

:把10个随机数存储到集合中,且不重复

 1             Random rd = new Random();
 2             for (int i = 0; i < 10; i++)
 3             {
 4                 int n = rd.Next(0, 10);
 5                 if (!list.Contains(n))
 6                 {
 7                     list.Add(n);
 8                 }
 9             }
10             for (int i = 0; i < list.Count; i++)
11             {
12                 Console.WriteLine(list[i]);
13             }

完成。

原文地址:https://www.cnblogs.com/KTblog/p/4456398.html