生成器函数找素数

 1 '''
 2 编写一个生成器函数myprimes(start, end),
 3 实现[start, end)范围内的所有素数计算2 3 5 7. ...
 4 (2,100)
 5 '''
 6 
 7 def foo(start,end):
 8     n = []
 9     m = []
10     for i in range(start,end):
11         m.append(i)
12         for j in range(2,int(i/2)+1):
13             if i % j == 0:
14                 n.append(i)
15                 break
16     su = list(set(m)-set(n))
17     for i in su:
18         yield i
19 def func(start,end):
20     for i in foo(start,end):
21         print(i)
22 
23 func(2,10)

版本二:

 1 def myprime(x):
 2     if x <= 1:
 3         return False
 4     for i in range(2, x):
 5         if x % i == 0:
 6             return False
 7     return True
 8 def myprimes(start, end):
 9     for i in range(start,end):
10         if myprime(i):
11             yield i
12 print([x for x in myprimes(1, 10)])
为什么要坚持,想一想当初!
原文地址:https://www.cnblogs.com/JerryZao/p/8808627.html