C++-hihoCode1546-[快速幂]

枚举子集,要求子集的min+max<=k,求子集个数,答案对1000000007取模

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 const int maxn=100010,MOD=1000000007;
 4 typedef long long ll;
 5 int a[maxn];
 6 int quick_pow(ll a,ll b){
 7     ll ans=1;
 8     for(;b;a=(a*a)%MOD,b>>=1)if(b&1)ans=(ans*a)%MOD;
 9     return ans;
10 }
11 int main(){
12     int n,k,ans=0;
13     scanf("%d%d",&n,&k);
14     for(int i=1;i<=n;i++)scanf("%d",&a[i]);
15     sort(a+1,a+n+1);
16     for(int l=1,r=n;l<=n;l++){
17         while(l<=r&&a[l]+a[r]>k)r--;
18         if(l<=r)ans=(ans+quick_pow(2,r-l))%MOD;            
19     }
20     cout<<ans<<endl;
21     return 0;
22 }
~~Jason_liu O(∩_∩)O
原文地址:https://www.cnblogs.com/JasonCow/p/12348218.html