AcWing算法提高课【第四章高级数据结构】线段树

最大数

链接:https://www.acwing.com/problem/content/1277/

代码:

 1 #include <bits/stdc++.h>
 2 
 3 using namespace std;
 4 
 5 const int N = 200010;
 6 
 7 struct Node 
 8 {
 9     int l, r, mx;
10 }tr[N * 4];
11 
12 int m, p;
13 
14 void build(int u, int l, int r)
15 {
16     tr[u] = {l, r};
17     if (l == r) return;
18     int mid = (l + r) >> 1;
19     build(u << 1, l, mid), build(u << 1 | 1, mid + 1, r);
20 }
21 
22 void change(int u, int x, int v)
23 {
24     if (tr[u].l == x && tr[u].r == x) 
25     {
26         tr[u] = {x, x, v};
27         return;
28     }
29     
30     int mid = (tr[u].l + tr[u].r) >> 1;
31     if (x <= mid) change(u << 1, x, v);
32     if (x > mid) change(u << 1 | 1, x, v);
33     tr[u].mx = max(tr[u << 1].mx, tr[u << 1 | 1].mx);
34 }
35 
36 int query(int u, int l, int r)
37 {
38     if (l <= tr[u].l && tr[u].r <= r) 
39     {
40         return tr[u].mx;
41     }
42     
43     int mid = (tr[u].l + tr[u].r) >> 1;
44     int v = 0;
45     if (l <= mid) v = query(u << 1, l, r);
46     if (r > mid) v = max(v, query(u << 1 | 1, l, r));
47     return v;
48 }
49 int main()
50 {
51     cin >> m >> p;
52     
53     build(1, 1, m);
54     
55     int last = 0, n = 0;
56     while (m -- ) 
57     {
58         char op[2];
59         int x; 
60         cin >> op >> x;
61         if (*op == 'Q')
62         {
63             last = query(1, n - x + 1, n);
64             cout << last << "
";
65         }
66         else 
67         {
68             change(1, n + 1, (x + last) % p);
69             n ++;
70         }
71     }
72     
73     return 0;
74 }
View Code
原文地址:https://www.cnblogs.com/Iamcookieandyou/p/14691554.html