AC日记——[Ahoi2013]作业 bzoj 3236

3236

思路:

  莫队+树状数组维护;

代码:

#include <cmath>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>

using namespace std;

#define maxn 100005

struct QueryType {
    int l,r,a,b,id;
};
struct QueryType qu[maxn*10];

int n,sum[maxn],sum_[maxn],ti[maxn],ans[maxn*10][2];
int ai[maxn],size,bel[maxn],m;

inline void in(int &now)
{
    char Cget=getchar();now=0;
    while(Cget>'9'||Cget<'0') Cget=getchar();
    while(Cget>='0'&&Cget<='9')
    {
        now=now*10+Cget-'0';
        Cget=getchar();
    }
}

inline int lowbit(int x)
{
    return x&(-x);
}

inline void sadd(int x,int k)
{
    while(x<=n) sum[x]+=k,x+=lowbit(x);
}

inline int ssum(int p,int x)
{
    int res=0;p--;
    while(x) res+=sum[x],x-=lowbit(x);
    while(p) res-=sum[p],p-=lowbit(p);
    return res;
}

inline void tadd(int x,int k)
{
    while(x<=n) sum_[x]+=k,x+=lowbit(x);
}

inline int tsum(int p,int x)
{
    int res=0;p--;
    while(x) res+=sum_[x],x-=lowbit(x);
    while(p) res-=sum_[p],p-=lowbit(p);
    return res;
}

inline bool cmp(QueryType aaa,QueryType bbb)
{
    if(bel[aaa.l]==bel[bbb.l])
    {
        if(bel[aaa.r]==bel[bbb.r])
        {
            if(aaa.l==bbb.l) return aaa.r<bbb.r;
            else return aaa.l<bbb.l;
        }
        return bel[aaa.r]<bel[bbb.r];
    }
    else return bel[aaa.l]<bel[bbb.l];
}

inline void updata(int now,int x)
{
    int pre=ti[now];
    ti[now]+=x,sadd(now,x);
    if(pre==0&&ti[now]==1) tadd(now,1);
    if(pre==1&&ti[now]==0) tadd(now,-1);
}

int main()
{
    in(n),in(m),size=sqrt(n);for(int i=1;i<=n;i++) in(ai[i]),bel[i]=(i-1)/size;
    for(int i=1;i<=m;i++) in(qu[i].l),in(qu[i].r),in(qu[i].a),in(qu[i].b),qu[i].id=i;
    sort(qu+1,qu+m+1,cmp);int l=1,r=0,pos;
    for(int no=1;no<=m;no++)
    {
        if(l<qu[no].l) for(int i=l;i<qu[no].l;i++) updata(ai[i],-1);
        else for(int i=l-1;i>=qu[no].l;i--) updata(ai[i],1);
        if(r>qu[no].r) for(int i=r;i>qu[no].r;i--) updata(ai[i],-1);
        else for(int i=r+1;i<=qu[no].r;i++) updata(ai[i],1);
        l=qu[no].l,r=qu[no].r,ans[qu[no].id][1]=ssum(qu[no].a,qu[no].b),ans[qu[no].id][2]=tsum(qu[no].a,qu[no].b);
    }
    for(int i=1;i<=m;i++) printf("%d %d
",ans[i][1],ans[i][2]);
    return 0;
}
原文地址:https://www.cnblogs.com/IUUUUUUUskyyy/p/6848379.html