Ac日记——Distances to Zero codeforces 803b

803B - Distances to Zero

思路:

  水题;

代码:

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>

using namespace std;

#define maxn 200005

int ai[maxn],bi[maxn],ci[maxn],n;

inline void in(int &now)
{
    char Cget=getchar();now=0;
    while(Cget>'9'||Cget<'0') Cget=getchar();
    while(Cget>='0'&&Cget<='9')
    {
        now=now*10+Cget-'0';
        Cget=getchar();
    }
}

int main()
{
    in(n);int cnt=maxn+1,pos=maxn+1;
    for(int i=1;i<=n;i++) in(ai[i]);
    for(int i=1;i<=n;i++) bi[i]=ai[i]?++cnt:cnt=0;
    for(int i=n;i>=1;i--) ci[i]=ai[i]?++pos:pos=0;
    for(int i=1;i<=n;i++) printf("%d ",min(bi[i],ci[i]));
    return 0;
}
原文地址:https://www.cnblogs.com/IUUUUUUUskyyy/p/6839878.html