给定斐波那契数列的项数求对应的数值的普通方法和优化处理

 1 /**
 2  给定斐波那契数列的项数求对应的数值
 3  参考：剑指Offer
 4  */
 5 #include <stdio.h>
 6 
 7 int fib(int n);
 8 long long fibonacci(unsigned int n);
 9 int main(int argc, const char * argv[]) {
10     
11     int n;
12     
13     while (1) {
14         
15         printf("请输入你想知道到的斐波那契数列的项数:	");
16         scanf("%d",&n);
17         int result = fib(n);
18         long long googResult = fibonacci(n);
19         printf("与之对应的斐波那契数列数列的值为:	%d	%lld

",result,googResult);
20         
21         
22     }
23     return 0;
24 }
25 
26 
27 int fib(int n){
28     
29     if(n == 0){
30         return 0;
31     }else if(n == 1){
32         return 1;
33     }else {
34         return fib(n-1) + fib(n-2);
35     }
36 
37 }
38 
39 //斐波那契数列数列求解优化
40 
41 long long fibonacci(unsigned int n){
42     
43     int result[] = {0,1};
44     if (n < 2){
45         return result[n];
46     }
47     long long smallest = 0;
48     long long smaller = 1;
49     long long temp = 0;
50     
51     for(int i=2; i<=n; i++){
52         
53         temp = smaller + smallest;
54         
55         smallest = smaller;
56         smaller = temp;
57         
58     }
59     return temp;
60     
61 }
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