最大公因数和最小公倍数

 1 # include <iostream>
 2 using namespace std;
 3 
//辗转相除法 4 int gcd(int a, int b) { 5 if (b == 0) return a; 6 return gcd(b, a%b); 7 } 8 9 int lcm(int a, int b) { 10 return a*b / gcd(a, b); 11 } 12 13 int main() { 14 int a, b; 15 while (cin >> a >> b) { 16 cout << gcd(a, b) << endl; 17 cout << lcm(a, b) << endl; 18 } 19 return 0; 20 }
自己选的路,跪着也要把它走完------ACM坑
原文地址:https://www.cnblogs.com/IKnowYou0/p/6071211.html