1001 害死人不偿命的(3n+1)猜想 (15 分)

#include <iostream>
using namespace std;
int main(){
    int n, count = 0;
    cin >> n;
    while (n != 1){
        if (n % 2 != 0)
            n = (3 * n + 1) / 2;
        else
            n /= 2;
        count++;
    }
    cout << count << endl;
    return 0;
}
原文地址:https://www.cnblogs.com/Hk456/p/10712318.html