leetcode -有效的字母异位词 python&C++

C++解题代码：

class Solutiion {
public:
    bool isAnagram(string s, string t) {
        int *data = new int[26]();
        int n = s.length();
        int m = t.length();
        int temp;
        if(n!=m)
            return false;
        for(int i = 0; i < m; i++){
            temp = s.at(i);
            data[temp - 'a']++;
        }

        for(int i = 0; i < n; i++){
            temp = t.at(i);
            data[temp - 'a']--;
            if(data[temp - 'a'] < 0)
                return false;
        }
    return true;

    }
}

Python3解题代码：

class Solution:
    def isAnagram(self, s: str, t: str) -> bool:
        if len(s) != len(t):
            return False


        def = {}
        for c in s:
            d[c] = d.get(c, 0) + 1


        for c in t:
            d[c] = d.get(c, 0) - 1
            if d[c] < 0:
                return False
        return True

class Solution:
    def isAnagram(self, s: str, t: str) -> bool:
        dic = {}
        
        for i in s:
            if i in dic:
                dic[i] += 1
            else:
                dic[i] = 1
                
        for i in t:
            if i not in dic or dic[i] <= 0:
                return False
            dic[i] -= 1
        
        for i in dic:
            if dic[i] != 0:
                return False
        return True