python 用基姆拉尔森计算公式求出某一天是星期几

代码:

RiQi = input("输入以下格式日期"year-month-day":") #输入日期
pingnian = [31,28,31,30,31,30,31,31,30,31,30,31]
runnian = [31,29,31,30,31,30,31,31,30,31,30,31]
weekday = ['一','二','三','四','五','六','日']
year = int(RiQi[0:4]) # 得到年
temp1 = RiQi.find('-')
temp2 = RiQi.rfind('-')
month = int(RiQi[5:temp2]) # 得到月
day = int(RiQi[temp2+1:])  # 得到日
Day = 0
RunNian = ((year%4==0 and year%100!=0) or year%400==0) #判断是否是闰年
if RunNian:  # 闰年
    for i in runnian[0:month-1]: # 注意索引从0开始,所以month-1
        Day = Day + i
else:   # 平年
    for i in pingnian[0:month-1]:
        Day = Day + i
Day = Day + day
temp = ((year-1)+(year-1)//4-(year-1)//100+(year-1)//400+1)%7
Weekday = (Day+temp-1)%7
print("今天是星期",weekday[Weekday-1])

也可以参考另外一篇文章
python判断天干地支年份

原文地址:https://www.cnblogs.com/HBU-xuhaiyang/p/13111415.html