jzoj6284

题意

父亲节点较小的树期望高度。(nle 200)

做法

(dp_{i,j})(i)个点选出(j)个点组成的概率
(dp_{i,j}=dp_{i-1,j-1} imes frac{j-1}{i}+dp_{i-1,j} imes frac{i-j}{i})
(f_{i,j})(i)点组成高度为(j)的树
(f_{i,j}=g_{i-1,j-1})
(g_{i,j})(i)点组成最大高度为(j)的树的森林
(g_{i,j}=sumlimits_{k=1}^i dp_{i,k} imes f_{k,j} imes g_{i-k,j})

原文地址:https://www.cnblogs.com/Grice/p/12878370.html