jzoj6002

题意

做法

(N=lfloorfrac{n-1}{2} floor)(ans=sumlimits_{i=1}^{N}sumlimits_{j=2 i+1}^n(y-2)!{j-2choose y-2}(n-y)!=(y-2)!(n-y)!sumlimits_{i=1}^{N}({n-1choose y-1}-{2i-1choose y-1}))

(A_{y-1}={1choose y-1}+{3choose y-1}+...+{2N-1choose y-1},B={2choose y-1}+{4choose y-1}+...+{2Nchoose y-1})

(A_{y-1}+B_{y-1}={2N+1choose y})(A_{y-1}+A_{y-2}=B_{y-1}),则:

[A_{y-1}=frac{{2lim+1choose y}-A_{y-2}}{2} ]

(A)可以(O(n))递推出来,预处理即可

原文地址:https://www.cnblogs.com/Grice/p/12659289.html