HDU 2057 A + B Again

A + B Again

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 12317    Accepted Submission(s): 5387

Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !
 
Input
The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.
 
Output
For each test case,print the sum of A and B in hexadecimal in one line.
 
Sample Input
+A -A
+1A 12
1A -9
-1A -12
1A -AA
 
Sample Output
0
2C
11
-2C
-90
 
Author
linle
 
Source
 
Recommend
linle
 
代码:
#include<stdio.h>
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
    __int64 a, b;
    while(scanf("%I64X%I64X",&a,&b)!=EOF)
    {
        __int64 sum =a + b;
        if(sum < 0)
        {
            sum =- sum;
            printf("-");
        }
        printf("%I64X
",sum);
    }
}
原文地址:https://www.cnblogs.com/GODLIKEING/p/3364463.html