Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 223816 Accepted Submission(s): 54902
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
Author
DOOM III
思路：
代码:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int n,sum=0,i;
while(scanf("%d",&n)!=EOF)
{
for(i=1;i<=n;i++)
sum=sum+i;
printf("%d ",sum);
sum=0;
}
}
#include <stdlib.h>
int main()
{
int n,sum=0,i;
while(scanf("%d",&n)!=EOF)
{
for(i=1;i<=n;i++)
sum=sum+i;
printf("%d ",sum);
sum=0;
}
}